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)`. Because we finally need to find this path .-Can’t use traditional dfs: directed node can’t point to the previous point; all nodes must be traversed by `save parent` #### Identify this is a union-find problem-see the form of weak component: a point Point to all, then all points have a common parent, and then it is necessary to find these points. -Why can’t it start from a point, such as A, and print all its neighbors directly:-If it is the turn of point B, because it is directed, it doesn’t know the situation of A, or how to continue to add or start. -So, put all the points related to A, or the next points related to A’s neighbors, into union-find, so that these points have Common parents.-The final output idea:-Make a map <parent ID, list>. -Didn’t we save the parent for each num before? -Each num has a parent, and then different parents create a different list. -Finally, just take out all the lists in the Map. “` /* LintCode Find the number Weak Connected Component in the directed graph.
